what is an equation of the line that passes through the point (0, 4) and is perpendicular to the line whose equation is y = −12x + 3?

Answer 1

line perpendicular to y= -12x +3

has negative inverse slope = 1/12

through point (0,4) has y intercept = 4

is line y = x/12 +4

Answer 2

y = mx + b (point-slope form)

For y = -12x + 3, the slope is -12, the y-int (b) is 3.

A perpendicular line will have a slope that is the negative reciprocal, in this case 1/12.

So the new equation is y = (1/12)x + b

We can use the ordered pair (0,4) to find b.

4 = (1/12)0 + b, so b = 4

The perpendicular is y = (1/12)x + 4

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