The sums (2,3,4,5,6,7,8,9,10,11,12) have the probabilities (1,2,3,4,5,6,5,4,3,2,1)/36 (easy to remember pattern, but you can count out the number of ways of getting a sum/62 possible sums).
P(sum>8) = P(9) + P(10) + P(11) + P(12) = (4+3+2+1)/36 = 5/18
P(sum is odd) = P(3) + P(5) +...
I'll leave the second one to you.
Please consider a tutor. Take care.