Write the equation of a line perpendicular to the line y = 3/2x - 6 and passes through (-2, 8).

Answer 1

y=(-2/3)x+b

8=4/3 +b

b=6 2/3 = 20/3

y=-2x/3 +20/3 is the perpendicular line through the given point, in slope intercept form

slope = negative inverse of 3/2, intercept = b =20/3