need help with math

Question

An object is thrown upward at a speed of 184 feet per second by a machine from a height of 14 feet off the ground. The height H of the object after T seconds can be found using the equation h=−16t^2+184t+14h

When will the height be 29 feet?

When will the object reach the ground

Answer 1

h=29= -16t^2 +184t + 14

16t^2 -184t = 43

t^2 - 23t/2 = 43/16

(t- 23/4)^2 = 43/16 + (23/4)^2

t = 23/4 +/- sqr[43/16 +(23/4)^2] seconds when it's 29 feet high

h=0 = -16t^2 +184t +14 when it hits the ground,

solve for t the same way

complete the square, factor or quadratic formula