Radical Functions

Question

Given the function f(x)=√−3x+3f(x)=-3x+3, calculate the following real values. If the output is not a real number, enter DNE.DNE.

a) f(−2)=f(-2)= 

b) f(−1)=f(-1)= 

c) f(0)=f(0)= 

d) f(1)=f(1)= 

e) f(2)=



Answer 1

Tra'von, your question may have been garbled enroute to Wyzant, but it's incomprehensible as is. It shows up asking about "the function f(x)=√−3x+3f(x)=-3x+3," That's not a function, but f(x) = √−3x+3 is; so is f(x) = 3x+3. ??

In addition, there's a lot of strange repetition. In "If the output is not a real number, enter DNE.DNE.", there obviously should be only one "DNE". Question a) appears as f(−2)=f(-2)=etc.

Please clarify and I'll give you a real answer! -).