
Yefim S. answered 12/11/22
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Center: x = 0 ,y = 0; (0, 0) is center; a/b = 1/2; a = 4; b = 8; c2 = 16 + 64 = 80; c = 4√5
Foci (0, - 4√5); (0, 4√5); Asymptots y = ±1/2x. Equation of hyperbola: y2/16 - x2/64 = 1