Inactive Tutor answered 12/08/22
Tutor
New to Wyzant
Since 2i is a root -2i is also a root.
P(x) = a(x - 3)(x - 2i)(x + 2i)
P(x) = a(x - 3)(x^2 + 4)
P(x) = a(x^3 - 3x^2 + 4x - 12)
Emily G.
asked 12/08/22P(x) is a 3rd degree polynomial with zeros 3 and 2i
Inactive Tutor answered 12/08/22
Since 2i is a root -2i is also a root.
P(x) = a(x - 3)(x - 2i)(x + 2i)
P(x) = a(x - 3)(x^2 + 4)
P(x) = a(x^3 - 3x^2 + 4x - 12)
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