find three consecutive integers such that 4 times the first is 49 more than the sum of the second and third

Answer 1

Hi Alexis N

26, 27, and 28

Let your three consecutive numbers be represented as follows:

First number = x

Second number = (x+1)

Third number = (x+2)

According to the information given

4x = 49 + (x+1) + (x + 2)

Can you just solve for x then plug that in to get the rest of the numbers?

Hope this helps, if you have questions just write back.