
William W. answered 12/06/22
Top Pre-Calc Tutor
We are not told which direction the Ferris wheel rotates but I'll assume its a standard counterclockwise direction. Here is a sketch:
For problem 1, the starting position at 3:00 would be a height of zero since we are measuring height above center. As the wheel rotates, the rider reaches a maximum height at the "12:00" position which is 90° or π/2 in a standard unit circle. The height could be modeled by a standard "sine" function and so we can use y = sin(θ) as our base equation. We would need to multiply by the amplitude which is 12 which makes it y = 12sin(θ). We are also not told how fast the wheel rotates. So we can introduce a variable into the equation to cover that. We can use "P" for period (the time it takes to go all the way around from 3:00 to 3:00). We can also entitle the function "h" for height. The function then would be:
h(θ) = 12sin[((2π)/P)θ]
The only difference between this equation and the one for problem 2 is the addition of the distance off the ground (17 meters) so the equation for problem 2 would be:
h(θ) = 12sin[((2π)/P)θ] + 17
Odai A.
The problem isn't looking for time so would I just change the function to 12sin[((2π))θ] instead?12/07/22