Find the equation of the quadratic function given its vertex (-4,3) and the origin V(0,0)

Question

1. Plz tell me the procedures too I'm having a hard time in solving this thank you in advance

Answer 1

y = a(x+4)^2 +3 is an vertical parabola, a quadratic function in vertex form, with vertex = minimum point = (-4,3). without more information a could equal any number. a>0 if upward opening. a<0 if downward opening.

y =ax^2 has vertex = (0,0)

general formula is

y = a(x-h)^2 + k where (h,k) = the vertex

if a=0, it's linear, a horizontal line, a function

but not a quadratic function

an infinite number of equations are possible quadratic relations, with the given vertices, but none are functions except a vertical parabola