Marcus has saved $340 to buy a new tablet. All of his money is in the form of $10 and $20 bills. He has 5 more $20 bills than $10 bills. How many of each type of bills does Marcus have?

Answer 1

Suppose Marcus has x number of 10$ and y number of 20$ bills.

Since the total is 340$, it implies

10x+20y=340 .........(1)

Now he has 5 more 20$ bills than 10$ bills, i.e.

y=x+5 .....(2)

substituting y=x+5 in (1), we get

10x+20(x+5)=340

=> 30x+100 =340

=> 30x=240 => x = 8

and from (2)

y=13

So Marcus has 8 number of 10$ and 13 number of 20$ bills.

Answer 2

Hi August G

10x + 20(x + 5) = 340

Can you do PEMDAS then solve for x?

If you have any questions let me know.