One number added to three times another number is 24. Five times the first number added to three times the other number is 36. Find the numbers

Question

systems

Answer 1

One number (X) added to (+) three (3) times (*) another number (Y) is (=) 24.

x+3y=24

Five (5) times (*) the first number (X) added to (+) three (3) times (*) the other number (Y) is (=) 36

5x+3y=36

Now solve the system of equations using substitution of elimination method.

1. x+3y=24
2. 5x+3y=36

You can change equation 1 by subtracting 3y from both sides

x=24-3y

Substituting equation 1 for x in equation 2

5(24-3y)+3y=36

Now solve for y

120 - 15y +3y = 36

120 -12y = 36

-12y = -84

y = 7

Now use your answer for y to find x. You can substitute 7 for y in equation 1 or 2, with the same result. Here I will use equation 1.

x+3y=24

x+3(7)=24

x+21=24

x=3

Answer 2

a + 3b = 24

5a + 3b = 36

Try subtracting the top equation from the bottom equation.