the height of a trangle is 12 cm longer than the base. The area is 54 cm^2. Find the lengths of its base and height

Question

asap

Answer 1

54=hb/2= (12+b)b/2

b^2+12b =108

b^2 +12b +36 = 108+36

(b+6)^2 = 144

b +6 = 12

base = -6+12= 6 cm

height = 18 cm

Area = bh/2 = 18(6)/2=54 cm^2

or you could have factored

b^2 +12b - 108 = 0

(b-6)(b+18) = 0

b -6=0

b = 6

h = 6+12 = 18