10.3 applications

Question

Find two positive numbers whose difference is 9 and whose product is 2332

Answer 1

x-y=9

y=x-9

xy=2332

x(x-9)=2332

x^2-9x - 2332=0

(x-53)(x+44) = 0

x =53 or -44

y =44 or -53

or

use the quadratic formula

x=9/2+/-.5sqr(81+4(2332))

the numbers are 53 and 44