The sum of three numbers is 86. The first number is 10 less than the second. The third number is 2 times the first. What are the numbers

Question

The sum of three numbers is 86. The first number is 10 less than the second. The third number is 2 times the first. What are the numbers

Answer 1

F+S+T = 86

F=S-10

T = 2F = 2S-20

S-10 + S + 2S-20 = 86

4S = 86+20+10 = 116

S= 116/4 = 29 = Second number

F= 29-10 = 19 = First number

T = 2(19) = 38

19+29+38= 86