Raymond B. answered 06/03/23
Math, microeconomics or criminal justice
680 days decays 64%
.64 = e^680r were r = daily decay rate
ln.64 = 680r
r = ln.64/680
half life is > 680 days, and when
1/2 = e^(ln.64/680)t
solve for t
ln.5 = t(ln.64/680)
t = ln.5/(ln.64)/680)
100 to 75 is less than 680 days and when
75/100 = e^(ln.64/680)t
solve for t
t = ln.75/((ln.64)/680)
use a calculator with a natural log function