find the three consecutive integers such that five times the second integers is equal to three times the sum of the other two, plus two. help please

Answer 1

-3, -2, -1 are 3 consecutive integers

where 5 times -2 = [3 times -1+(-3)] +2

-10 = -12+2=-10

UNLESS you somehow intended to say

5 times Second= 3 times (Third+First + 2)

5S = 3(S+1+S-1+2) = 6S+6

S=-6

F=-7

T=-5

5(-6) = -30

3(-5-7+2)= 3(-10) = -30

then the numbers are

-7, -6, -5

but the way the problem is written go with the 1st solution

-3,-2, -1