Write an equation of the line that passes through 3,1 and 0,10

Question

just a math problem im having problems on, i hate these types of problems but eh

Answer 1

Recall that the equation for a line is y = mx + b. M is your slope so calculate your change in x divided by your change in y. If you take the time to plot the two points you will notice that it produces a negative slope. your change in y is 1 - 10 = -9 and your change in x is 3 - 0 = 3. So the Δy/Δx = -3. Now your equation is

y = -3x + b

Recall that your "b" is simply the y intercept or the point at which x=0. Therefore you've already been given that with the point (0,10), so you can skip to knowing that b = 10. However, there is nothing wrong with plugging either of these points into the equation and solving for b. Either way you are left with the following:

y = -3x + 10

Try plotting this and double check that it makes sense. That it crosses through both given points, that the slope is negative etc.

Hope this helps.

Answer 2

Use the 2 point form: (10-1)/(0-3) = (y-10)/x.

Use algebraic manipulation to bring it to the form you want.

BTW: What's to hate?