Raymond B. answered 11/21/22
Math, microeconomics or criminal justice
15 hours 18.5 cm
32 hours 10 cm
28 hours x cm where 18.5<x<10 and x closer to 10 than 18.5
h(t) = y = mx +b
18.5 = 15m + b
10 = 32m + b
2 equations, 2 variables, solve by substitution, elimination or matrix algebra
18.5(32) =15(32)m + 32b
10(15) =32(15)m + 15b
subtract
32b-15b = 18.5(32)- 10(15
17b = 592-150=442
b = 442/17 = 26
10=32m+26
32m =10-26 =-16
m =-16/32 = -1/2
h(t) = -t/2 +26
h(28) = -28/2+26 =-14+26 = 12 cm after 28 hours
h(0) = 26 cm initially at time t=0
Chelle H.
Thank you so much!!11/21/22