what is the nth term of 4, 9, 14, 19, 24, 29

Question

I'm practicing for my 1st Semester Exam, and I am bad with terms and sequences

Answer 1

a6 = a5 +5 =24+ 5 = 29

a7 =a6 +5 = 29+5 = 34

a8 = a7 +5 = 34+5 =39

a9 = a8+ 5 =39+5 = 44

neth term = an =a1 + d(n-1)

an=a1 +5(n-1) = a1 +5n-5 = 4+5n-5 = 5n-1

where d=common difference =5, a1 =4

9th term = a9 = 4+5(9-1) = 4+5(8) =4+40=44

or

a9 = 5(9)-1 =45-1 =44

It's an arithmetic sequence

4,9,14,19,24,29,34,39,44, 49, 54, 59, 64, ...

the last digit of all terms alternates between 4 and 9

4 for an odd term

9 for an even term

9th term is even and ends in a 4

tens digit = 0,0,1,1,2,2,3,3,4,4, 5,5, ...