Find zeros at which f flattens out

Question

F(x)=(x+3)(x-4)^2

Answer 1

F(x) = (x+3)(x-4)^2

2 zeros, -3 and 4

4 is the zero where the slope =0, due to the multiplicity 2

graphically at (4,0) the curve is tangent to the x axis

the function is "flat" when the slope =0

slope =0 when F'(x) =0