Emily B.

asked • 11/17/22

Math Problem that i need hellp with

A company estimates that 2% of their products will fail after the original warranty period but within 2 years of the purchase, with a replacement cost of $350.


If they want to offer a 2 year extended warranty, what price should they charge so that they'll break even (in other words, so the expected value will be 0)

Hunter E.

P(no failure within 2 years after warranty) = 1 - 0.02 = 0.98 If a customer buys an extended warranty, the company will receive the warranty price upfront. If a product fails, the company will have to replace it at a cost of $350. If a product does not fail, the company will keep the warranty price as profit. Let's denote the warranty price as X. Then, the expected value of selling an extended warranty is: E(X) = 0.98X + 0.02(-$350) = 0.98X - $7 To break even, the expected value of selling an extended warranty should be 0, so: 0.98X - $7 = 0 0.98X = $7 X = $7 / 0.98 X = $7.14 (rounded to the nearest cent) Therefore, the company should charge at least $7.14 for a 2 year extended warranty to break even.
Report

04/16/23

1 Expert Answer

By:

Ajay N. answered • 05/18/23

Tutor
5 (3)

Excel in Teaching Finite Math

Ajay N.

You can also do the strict 'statistics and probability' outcomes and probabilities of outcome variation of this approach for the solution: Outcomes are x (for Revenue or price to charge in the warranty offer) and -(350-x) ...which equals =350+x. So outcomes are x and [-350+x]. The probabilities of outcome are 1-0.02 = 0.98 & 0.02 respectively. So, to solve, follow the step-by-step solution approach below: x*(0.98) + (-350+x)*0.02 = 0 [Break even expected value amount] 0.98x -7+0.02x = 0 -7 + 1x = 0 1x = 7 x= $7 (should be charged per person for the 2 year extended warranty in order for the company to break even)
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05/18/23

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