One angle is 40degrees° greater than 8 times its complement. Find the measure of the larger of the two angles. Round your answer to two decimal places if necessary.

Question

One angle is 40degrees° greater than 8 times its complement. Find the measure of the larger of the two angles. Round your answer to two decimal places if necessary.

Answer 1

x = 40 +8y, where y= smaller complement, x = the larger

x+y =90

40+8y = y= 90

9y= 50

y = 5.555...

y = 5.56 degrees

x = 84.44 degrees

x = 40+8(50/9) = 40+400/9

x = 40 +44.444...

x = 84.44 degrees