Maths- sketching graphs

Question

An arch is modelled by the relationship:

(x − 3)^2 + y^2 = 9

Information about the relationship:

• x is the horizontal coordinate along the arch

• y is the vertical coordinate along the arch

• both x and y are measured in metres

• The range of values for x are:

0 ≤ 𝑥𝑥 ≤ 6

• Disregard the negative y values

Sketch the graph of this relationship

What is the horizontal distance along the ground from one side of the arch to the other

side of arch?

What is the height of the arch?

Answer 1

(x-3)^2 + y^2 = 9 = 3^2

(x-h)^2 + (y-k)^2 = r^2 where center = (h,k) and radius =r

center is (3,0)

it's a circle with radius = 3

height = the diameter = 2(3) = 6 = horizontal distance from left to right side