Mark M. answered 11/15/22
Mathematics Teacher - NCLB Highly Qualified
w = 0.0071(153) − 0.09(152) + 0.48(15),
Jaylin J.
asked 11/15/22The weight of an ideal round-cut diamond can be modeled by
w = 0.0071d3 − 0.09d2 + 0.48d,
where w is the diamond’s weight (in carats) and d is its diameter (in millimeters). According to the
model, what is the weight of a diamond with a diameter of 15 millimeters?
Mark M. answered 11/15/22
Mathematics Teacher - NCLB Highly Qualified
w = 0.0071(153) − 0.09(152) + 0.48(15),
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