B. Find the numerical values of ∂z∂s and ∂z∂t when (s,t)=(5,−5).

Question

) Suppose z=x2sinyz=x2sin⁡y, x= -3s^2+2t^2, y=6st

A. Use the chain rule to find ∂z∂s∂z∂s and ∂z∂t∂z∂t as functions of x, y, s and t.

dz/ds = -12sxsiny+6tx^2cosy (I got this right)

dz/dt = 8txsiny+6sx^2cosy (I got this right)

B. Find the numerical values of ∂z∂s∂z∂s and ∂z∂t∂z∂t when (s,t)=(5,−5)(s,t)=(5,−5).

∂z/∂s(5,−5)= I tried multiple times and I havent gotten it right

dz/dt(5,-5)= I tried multiple times I havent gotten the answer.

X=-25

Y=-150

Answer 1

x and y and s and t are correct. You undoubtedly have no trouble substituting into the correct expressions for dz/ds and dz/dt.... Is your calculator in radians? (For dz/ds, I got -12038.6)

Good luck!