(x+yi) i-2/(2x-yi)+1=1+2i

Question

Find x and y, where x is the real part and y is the imaginary part

Answer 1

(x-yi)i = xi+y

-2/(2x-yi)= -2(2x+yi)/(4x^2+y^2)

= (-4x-2yi)/(4x^2+y^2)

add the above to equal 1+2i

y-4x/(4x^2+y^2) = 1= the real part

x-2y/(4x^2+y^2) = 2 = the imaginary part

is this a real problem? if so your instructor is a tad sadistic. or your textbook has an error somewhere