Find the equation of a line perpendicular to y=X+6 that passes through the point (3,1)

Answer 1

y=-x+4 is the perpendicular line through (3,1)

replace x by 3 and y by 1 to get

1=-3+4

1=1

slope of a perpendicular line is the negative inverse of 1, which is -1 = coefficient of the x term when the linear equation is solved for y