what are the x-values in y=x^2+8x-15, y=x^2+12+29

Answer 1

y = x^2 + 8x +15

y = (x+5)(x+3)

x intercepts or roots = -3 and -5

y =x^2 + 12x +27

y = (x+9)(x+3)

x = -3 and -9 = roots, solutions, y intercepts or zeros

(problem was modified to make it easier to solve or more understandable, or both)

closer to as written though

x^2 +8x -15

x = -4 +/-sqr31

x^2 +12x +29

x = -6+/-sqr7

irrational roots come in conjugate pairs

whatever the original quadratics, they were upward opening parabolas

that intersect the x axis twice each, with vertices below the x axis,

y intercepts above the x axis