write an equation in slope point form for the line that contains the points (5,4) and is perpendicular to the given line "-y+2=5x"

Question

write an equation in slope point form for the line that contains the points (5,4) and is perpendicular to the given line "-y+2=5x"

Answer 1

-y+2 = 5x

solve for y

y =-5x +2

the slope = the coefficient of the x term, when the linear equation is solve for x

= -5

a perpendicular line has a negative inverse slope = 1/5

in point slope form the equation of the perpendicular line through (5,4) is

y-4 = (1/5)(x-5)

in slope intercept form the equation is

y= (1/5)x +3

in standard form the equation is

x-5y = -15

in general form it's

x-5y +15 = 0