Raymond B. answered 11/10/22
Math, microeconomics or criminal justice
1) thomas' distance = 40t where t = hours
2) james' distance =200- 55t
3) 4:06 pm
200 = (40+55)t
t=200/95= 40/19= about 2 hours and 6 minutes to collide = 4:06 pm
4) 115.5 miles
55x 40/19 = 220/19 = about 55x2.1 = 115.5 miles from weston when colliding
if they collided halfway then james left later than 2 pm
5) time james left
thomas left at 2pm going 100 miles in 2,5 hours
100=40t
t= 2.5 hours =2+2.5 = 4:30 pm collision
for james
55t=100
t=100/55= 20/11=1 9/11 hours to go 100 miles
4:50 minus 1 9/11 hours = 3:01 pm when james left