
Emily W. answered 11/10/22
Teaching Algebra II for High School and College
Lets represent the side length with s
s = 2x^5
If this side length is being doubled, our new equation for the side length is
2s = 2*2x^5 = 4x^5
We are going to write the volume equation by putting 4x^5 where the side length should go.
V = side^3
V= (4x^5)^3
Power of a product law —> outer exponent multiples onto each inner exponent. (Remember 4 is really 4^1)
4^1–> 4^1*3 = 4^3
x^5–> x^5*3=x^15
V = 4^3 * x^15
The last step would be to simplify 4^3
4^3 = 4*4*4=64
V = 64x^15
Buk B.
thank u11/10/22