Write an equation in​ slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.

Question

Write an equation in​ slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.

(-7,-6);y=-2x+3

Answer 1

y=x/2 +b

-6 =-7/2 +b

b =-6 +7/2 = -5/2

y = x/2 -5/2

y = (1/2)x -5/2 is the equation through the point (-7,-6), in slope intercept form.

slope = 1/2 = the negative inverse of the slope of the original line's -2.

-5/2 = the y interept = the point (0, -5/2)