find the y intercept for P(x)=3(3x-2)^2(x+1)(x+2)

Answer 1

set x=0 solve for P(0)

= 3(0-2)^2(0+1)(0+2)

= 12(1)(2)= 24 = y intercept = the point (0,24)

or use a graphing calculator

x intercepts are -2, -1, 2/3

it's "W" or sort of UU shaped

middle top of the "W" just touches the x axis at (0, 2/3)