Find the 10th term of the geometric sequence whose common ratio is 1/2 and whose first term is 3.

Answer 1

a1 = 3

r= 1/2

an= 3(1/2)^(n-1)

a10 = 3(1/2)^9

a10 = 3/2^9=

a10 = 3/512

a10 = about 0.006

a1 = 3

a2 = 3/2

a3 = 3/4

a4 = 3/8

a5= 3/16

a6 = 3/32

a7 = 3/64

a8 = 3/128

a9 = 3/256

a10 = 3/512

a10 = about 0.006