Algebra Mathematics

Question

find two consecutive odd integers such that 86 more than the lesser is five times the greater

Answer 1

Hello Kamya, thank you for your question!

The key on this type of question is to find a way to model the information given using an equation.

In this case we would have

x + 86 = 5(x + 2) because we know that the integers have to be consecutive

Solving that for x gives

x + 86 = 5x + 10

76 = 4x

19 = x

That means that the first odd integer would be x = 19. Then the next one would be 19 + 2 = 21.

I hope that helps :)