The shorter leg of a right triangle is 8 less than the hypotenuse. The longer leg is 1 less than the hypotenuse. find the perimeter of triangle

Answer 1

h^2= (h-8)^2 + (h-1)^2

h^2 = h^2 -16h + 64 + h^2 -2h +1

-h^2 = 65 - 18h

-h^2 +18h -65 = 0

h^2 -18h +65= 0

(h-13)(h-5)=0

h= 5 or 13

h-1 = 12, or 4

h-8 = 5

5, 12, 13 sum to 30 = perimeter