Michael J. answered 03/19/15
Tutor
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Effective High School STEM Tutor & CUNY Math Peer Leader
x + 2y = 8 eq1
2x - 3y = 2 eq2
Multiply eq1 by 2 and keep eq2 the same.
2x + 4y = 16
2x - 3y = 2
Subtract both equations to eliminate the x terms.
7y = 14
y = 2
Substitute this value into eq2 to solve for x.
2x - 3y = 2
2x -3(2) = 2
2x - 6 = 2
2x = 8
x = 4
The solutions are
x = 4
y = 2