what is the equation of the line that passes through (-2,8) and (-4,-4)

Answer 1

First calculate the slope using the slope equation:

x₁ = -2, y₁ = 8, x₂ = -4, y₂ = -4 so:

m = (-4 - 8)/(-4 - -2) = (-12)/(-4 + 2) = -12/-2 = 6

Now, use the point-slope form of a line:

y - y₁ = m(x - x₁) and plug in "m", "x₁" and "y₁":

y - 8 = (6)(x - -2)

y - 8 = 6(x + 2)

y - 8 = 6x + 12

y = 6x + 20