Robert K. answered 10/29/22
Experienced Math Tutor Who Will Improve Both Understanding and Grades
f(x) = y = AB^x
18 = AB^3 (eq 1)
162 = AB^1 (eq 2)
Divide eq 1 by eq 2
18/162 = 1/9 = B^2
B = 1/3
y = A(1/3)^x
using eq 2 (easier) 162 = A(1/3)^1
162 = (1/3)A
A = 3(162) = 486
y = 486(1/3)^x
Check with eq 1
18 =? 486(1/3)^3
18 =? 486(1/27)
18(27) = 486 check
f(x) = 486(1/3)^x