Algebra help please?

Question

I'm stuck on this problem and hoping someone can help

A bank invested ​$370,000 last year in mutual funds. The conservative fund earned 9​%

simple interest. The growth fund earned 14​% simple interest. At the end of the​ year, the bank had earned

​$44,000 from these mutual funds. How much did it invest in each​ fund?

Answer 1

.14x + .09(370,000-x) = 44,000

.14x -.09x = 44,000 - .09(370,000)

.05x = 44,000- 33,300

x = 10,700/.05

x = $214,000 invested at 14%

370,000-214,000 = $156,000 invested at 9%

check the answers

.14(214000) -.09(156000,)

= 29,960 + 14,040= 44,000

44000/370000= about 11.9 or 12%= average rate of return

12-9= 3

14-12= 2

3/2 = 1.5 = about 214/156=1.4

with rounding errors, they seem about equal