seven order pairs for y=x^2-8

Question

seven order pairs for y=x^2-8

Answer 1

y=x^2 -8

vertex is one ordered pair, V(0,-8)

plug in other x values to get other ordered pairs

(1,-7) or (-1,-7)

(2,-4) or (-2,-4)

the equation describes an upward opening parabola with axis of symmetry x=0

vertex V(0,-8), = minimum = y intercept, x intercepts (sqr8,0) and (-sqr8,0)

(3,1) or (-3,1)

(4,8) or (-4,8)

that's about 11 ordered pairs. take your pick for 7