Suppose you want to draw a rectangle where the width is 3 inches more than the length and the diagonal is 6 inches longer than the length. What are the dimensions of the rectangle?

Answer 1

W= 3+L

D=6+L

D^2 = L^2 + W^2

(6+L)^2 = L^2 + (3+L)^2

36 +12L + L^2 = L^2 + 9 +6L + L^2

L^2 -6L - 27 = 0

(L-9)(L+3) = 0

L= 9 inches= Length

W = 12 inches= Width

D= 15 inches= Diagonal