Snow D.

asked • 10/23/22

please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Dominique throws a softball from the outfield. After 1 second, the ball is 10 feet high. After 4 seconds, the ball reaches its maximum height of 46 feet. After 7 seconds, it returns to a height of 10 feet. What is the equation of the quadratic function that models the height of the ball h(t) at time t?

h(t) = 4(t + 4)2 + 46

h(t) = −4(t − 4)2 + 46

h(t) = 2(t + 3)2 + 46

h(t) = −2(t − 3)2 + 46

1 Expert Answer

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Mark M. answered • 10/23/22

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It can only be #2 or #4.

Why not supstitute values and see which one solves?

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Snow D.

so what your saying is that it would be b becaus when i plug it in thats what i get... is that right?
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10/23/22

Dima S.

tutor
The maximum height, 46, it reaches at 3 seconds is the vertex. (3,46) Since they said maximum then your equation should be negative. F(x)= a(x-h)^2+k Where (h,k) is the vertex. K is the maximum at time h. Yes, b is correct.
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10/23/22

Peter R.

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Think you meant max ht at 4 secs. (vertex)
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10/23/22

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