The point (-3, -2) is on the line y = mx + b, which is perpendicular to the line y = -3x + 2. (2p) Find m and b.

Answer 1

m = 1/3, the negative invese of -3.

y = x/3 + b. Plug in the point (-3,-2) to solve for b=y intercept

-2=-3/3 +b

-2 =-1+b

b =-2 +1 = -1

y =x/3-1 b=-2, m= 1/3