Matt M. answered 10/23/22
Valedictorian, top 1% of graduates in the United States
Using Pythagoras theorem
C=√A² + B²
Insert the triangle lengths (they should be provided) into this equation. For a triangle with lengths of 5 and 3
C= √ 5² + 3²
First thing I do is square both sides changing the problem to:
C²=5²+3²
C²=25+9
C= √34.
*note some teachers may prefer the square root broken down rounding it to the nearest 10th or 100th, which in this problem would be C=5.83
A triangle with lengths of √3 and √6
C=√(√3)² + (√6)² original input
C² = (√3)² + (√6)² square both sides
C² = 3+6 The square root and squared values cancel each other out
C=√9 which can be further reduced to 3
I hope this makes sense and if you have any more questions I would be happy to assist in any way possible.