Asked • 10/18/22

Minimum value of the quadratic function

Find the minimum value of the quadratic function f(x) = x2 + 3

Inactive Tutor

Hello! The formula you may want to use to help you find minimums and maximums is x= -b/2a. This equation will find the x-value of the vertex (i.e. maximum OR minimum). Note that if the variable a is positive, the graph will quadratic function be in a U shape (vertex is a minimum). If the variable is negative the graph will be an upside down U shape (vertex is a maximum). Once you find the value of x, plug that value into your function to find the y value of your min/max. Hope this helps!
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10/18/22

Inactive Tutor

Oh! One more thing, a quadratic function is in the form f(x)= ax^2+bx+c. So in your problem, a=1 and b=0. Therefore the MINIMUM (since a is positive) is at x=0. When plugging in, f(0)= 0^2+3 = 3.
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10/18/22

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