Edward C. answered 03/19/15
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Caltech Grad for math tutoring: Algebra through Calculus
Let L = length of garden
Let W = width of garden
Twice as long as wide ==> L = 2*W
Area 620 ==> L*W = 620
Substitute the value for L from the 1st equation into the 2nd equation
(2*W)*W = 620
W^2 = 310
W = +- sqrt(310)
Width cannot be negative so discard the negative solution
W = sqrt(310) ~ 17.6 feet
L = 2*sqrt(310) ~ 35.2 feet
The retaining wall will be either 17.6 feet or 35.2 feet depending on whether Miss Powell builds it along the width or length of her garden.