A bag contains 6 red marbles and 7 white marbles. Two marbles are drawn in succession without replacement. Find the probabilities of the following events:

Question

A bag contains 6 red marbles and 7 white marbles. Two marbles are drawn in succession without replacement. Find the probabilities of the following events:

Answer 1

P(2R)= (6/13)(5/12)=30/156

P(2W)=(7/13)(6/12)=42/156

P(1R&1W)=1-P(2R)-P(2W)=84/156

P(1R&1W)=P(RW)+P(WR)

=(6/13)(7/12)+(7/13(6/12)=84/156