Find the equation of the line whose slope is -3 and which passes through the point (5,-2).

Answer 1

-3 = (y+2)/(x-5)

y = -3x+13

check the answer, plug in (5,-2), x=5, y =-2

-2 = -3(5)+13 = -15+13

slope = the coefficient of the x term, when the linear equation is solved for y = -3